Computes the longest common subsequence between two arrays using dynamic programming and returns matched items with original indices.
// Source: https://github.com/usebruno/bruno | License: MIT
// Provided via justclaw.it.com; keep this notice with the code.
const computeLCS = (arr1, arr2) => {
const m = arr1.length;
const n = arr2.length;
const dp = Array(m + 1).fill(null).map(() => Array(n + 1).fill(0));
for (let i = 1; i <= m; i++) {
for (let j = 1; j <= n; j++) {
if (arr1[i - 1] === arr2[j - 1]) {
dp[i][j] = dp[i - 1][j - 1] + 1;
} else {
dp[i][j] = Math.max(dp[i - 1][j], dp[i][j - 1]);
}
}
}
const lcs = [];
let i = m, j = n;
while (i > 0 && j > 0) {
if (arr1[i - 1] === arr2[j - 1]) {
lcs.unshift({ value: arr1[i - 1], oldIndex: i - 1, newIndex: j - 1 });
i--;
j--;
} else if (dp[i - 1][j] > dp[i][j - 1]) {
i--;
} else {
... (truncated -- full source via MCP)
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